Question

a 600-mL sample of nitrogen is warmed from 350K to 359K. find its new volume of the pressure remains constant

Answer 1

Charles's Law-

`\:\:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow\sf \underline{(V_1)/(T_1)=(V_2)/(T_2)}\\`

Where:-

• V₁ = Initial volume
• T₁ = Initial temperature
• V₂ = Final volume
• T₂ = Final temperature

As per question, we are given that -

• V₁=600 mL
• T₁ = 350K
• T₂ =359K

Now that we have obtained all the required values, so we can put them into the formula and solve for V₂ :-

`\:\:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow\sf \underline{(V_1)/(T_1)=(V_2)/(T_2)}\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2= (V_1)/(T_1)* T_2\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2= (600)/(350)* 359\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2= 1.71428..............* 359\\`

`\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf V_2 =615.4285................\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf\underline{ V_2= 615.42\:mL}\\`

Therefore, the new volume of the gas will become 615.42 mL when pressure remains constant.