Question

What is the inverse of the logarithmic function

f(x) = log2x?

f –1(x) = x2

f –1(x) = 2x

f –1(x) = logx2

f –1(x) = StartFraction 1 Over log Subscript 2 Baseline x EndFraction

Answer 1

Answer: The inverse of the logarithmic function f(x) = log2x can be found by interchanging the roles of x and y in the function and solving for y. The steps are as follows:

Step 1: Replace f(x) with y.

y = log2x

Step 2: Interchange x and y.

x = log2y

Step 3: Solve for y.

We need to isolate y on one side of the equation. To do this, we can rewrite the equation in exponential form. Recall that the logarithmic function with base b is defined as follows:

logb(x) = y if and only if b^y = x.

Using this definition, we can rewrite the equation x = log2y as follows:

2^x = y

This means that the inverse of f(x) = log2x is given by:

f –1(x) = 2^x

Therefore, the correct answer is:

f –1(x) = 2^x.

Explanation: