Answer: The sound level produced by a chorus of 43 singers will be 97.66 dB.
Step-by-step explanation:
Let I, the intensity of a sound produced by a singer, therefore, the intensity of the sound produced by 43 singers is equal to 43I. Therefore, the intensity is:
x = 10log(43I/Io)
x = 10log(43) + 10log(I/Io)
The second term in the equation is the sound intensity produced by a single singer. We calculate that the sound intensity of 36:
x = 10log(36) + 82.1 = 97.66 dB