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Complete the square to determine all solutions for x^2-4x=2

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Answer: To complete the square, we need to add and subtract the square of half the coefficient of x:

x^2 - 4x = 2

x^2 - 4x + 4 = 2 + 4 (adding and subtracting 4)

(x - 2)^2 = 6

Now we take the square root of both sides:

x - 2 = ±√6

Adding 2 to both sides gives:

x = 2 ± √6

So the solutions are:

x = 2 + √6, 2 - √6

Explanation:

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