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What is the polar form of 7 StartRoot 3 EndRoot minus 7 i?

User Tzach
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2 Answers

5 votes

Final answer:

The polar form of 7√3 - 7i is 14(cos(tan^(-1)(-7/(7√3))) + i*sin(tan^(-1)(-7/(7√3)))).

Step-by-step explanation:

To find the polar form of a complex number, we can express it in terms of its magnitude and angle. Let's consider the complex number 7√3 - 7i. To find its magnitude, we can use the Pythagorean theorem. The magnitude is √((7√3)^2 + (-7)^2) = √(147 + 49) = √196 = 14.

Next, we can find the angle by using the inverse tangent function. The angle is given by tan^(-1)(-7/(7√3)).

Therefore, the polar form of 7√3 - 7i is 14(cos(tan^(-1)(-7/(7√3))) + i*sin(tan^(-1)(-7/(7√3)))).

User Myat Min Soe
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4 votes

Answer:The polar form of 7 StartRoot 3 EndRoot minus 7 i is 14(cos(330o) + i sin(330o))

Step-by-step explanation:

User Fluxian
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