Answer:
I'm assuming that 1 is actually a point with coordinates (1, something) and you meant the point H(25,-16).
To find the equation of the line passing through two points (x1,y1) and (x2,y2), we can use the point-slope form:
y - y1 = m(x - x1)
where m is the slope of the line, which can be calculated as:
m = (y2 - y1) / (x2 - x1)
Using the points H(25, -16) and 1(-2.5, y), we have:
m = (-16 - y) / (25 - (-2.5)) = (-16 - y) / 27.5
Multiplying both sides by 27.5, we get:
-16 - y = -0.58x + b
where x is the x-coordinate and b is the y-intercept of the line. To find b, we plug in one of the points (let's use H) and solve for b:
-16 - (-16) = -0.58(25) + b
b = -16 - (-14.5) = -1.5
Therefore, the equation of the line passing through H(25, -16) and 1(-2.5, y) is:
y + 1.5 = -0.58(x + 2.5)
or:
y = -0.58x - 4.25
Note: I assumed that you meant H(25,-16) and I used -2.5 as the x-coordinate for point 1 because you didn't specify what it was.