Question

A circular path 2feet wide has an inner diameter of 550 feet . How much farther is it around the outer edge of the path than around the inner edge?

Answer 1

`L_c=12.56 \ \text{feet}`

Explanation:

From the question we are told that

Width of circular path
`w_c=2 \ \text{feet}`

Inner Diameter
`d_(in)=550 \ \text{feet}`

Outer diameter
`d_(out)=550+2*2` (inner diameter + 2 circular path width)

`d_(out)=550+4`

`d_(out)=554 \ \text{feet}`

Generally the equation for inner circumference of the circle is mathematically given by

`C_1=\pi d_(in)`

`C_1=3.14*550`

`C_1=1727 \ \text{feet}`

Generally the equation for outer circumference of the circle is mathematically given by

`C_2=\pi d_(out)`

`C_2=3.14*554`

`C_2=1739.56 \ \text{feet}`

Generally the difference in length of the two circumference is mathematically given by

`L_c=C_2-C_1`

`L_c=1739.56-1727`

`L_c=12.56 \ \text{feet}`