Trish is correct because the prime factorization of 48 will be the same regardless of which factors are chosen as the initial factors in the tree.
To see why, let's look at the prime factorization of 48:
48 = 2 × 2 × 2 × 2 × 3
No matter which factors are chosen as the initial factors, the same prime factors will eventually be found.
For example, if Donna's method is used, we could start with 6 and 8:
6 = 2 × 3
8 = 2 × 2 × 2
Then we could continue to factor each of these numbers until we reach prime factors:
6 = 2 × 3
8 = 2 × 2 × 2
= 2 × 2 × 2 × 3
= 2³ × 3
Now we have found all of the prime factors of 6 and 8, and we can combine them to get the prime factorization of 48:
48 = 2 × 2 × 2 × 2 × 3
If Larry's method is used, we could start with 4 and 12:
4 = 2 × 2
12 = 2 × 2 × 3
Then we could continue to factor each of these numbers until we reach prime factors:
4 = 2 × 2
12 = 2 × 2 × 3
= 2² × 3
Now we have found all of the prime factors of 4 and 12, and we can combine them to get the prime factorization of 48:
48 = 2 × 2 × 2 × 2 × 3
As we can see, the same prime factors are found regardless of which factors are chosen as the initial factors in the tree. Therefore, Trish is correct that the initial factors of 48 do not affect the prime factorization.