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How much energy (in Joules) would it take to warm 3.11 grams of gold by 7.9 oC

(specific heat capacity of gold = 0.130 J/g °C)

User Daigorocub
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1 Answer

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Step-by-step explanation:

3,11 g * 7.9 C * .130 J/(g C) = 3.19 J

See how the 'g' the 'C' cancel out and you are left with 'J ' for an answer?

User Esen
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