Question

The amount of energy needed to heat 4.3 g of a substance from 50.0°C to 80.0°C is 9.0 J. What is the specific heat capacity of this sample?

Answer 1

c = 0.0635 J/g°C

Step-by-step explanation:

We can use the formula for heat energy:

Q = m * c * ΔT

where Q is the heat energy absorbed by the substance, m is its mass, c is its specific heat capacity, and ΔT is the change in temperature. Rearranging the formula, we get:

c = Q / (m * ΔT)

Plugging in the given values, we get:

c = 9.0 J / (4.3 g * (80.0°C - 50.0°C))

c = 9.0 J / (4.3 g * 30.0°C)

c = 0.0635 J/g°C

Therefore, the specific heat capacity of the substance is 0.0635 J/g°C.