Answer:
325.38°C
Step-by-step explanation:
We can use the formula Q = mcΔT to solve this problem, where Q is the amount of heat transferred, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.
First, we need to calculate the amount of heat transferred:
Q = 92.3 J
Next, we need to calculate the change in temperature. We can rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
where ΔT is the change in temperature, Q is the amount of heat transferred, m is the mass of the substance, and c is its specific heat capacity.
Plugging in the values we have:
ΔT = 92.3 J / (2.3 g x 0.130 J/g °C)
ΔT = 300.38 °C
This means that the temperature of the gold has increased by 300.38 °C. Since the initial temperature was 25.0°C, the final temperature will be:
Final temperature = Initial temperature + ΔT
Final temperature = 25.0°C + 300.38 °C
Final temperature = 325.38 °C
Therefore, the final temperature of the gold is 325.38°C.