Answer:
h(x) = (x^2 - 64)
Explanation:
If the solutions to h of x = 0 are x = -8 and 8, then h(x) must be a quadratic function with roots at x = -8 and x = 8.
One way to write the quadratic function that satisfies these conditions is:
h(x) = (x+8)(x-8)
where a is some non-zero constant that determines the shape of the parabola.
Expanding the above equation, we get:
h(x) = (x^2 - 64)
Therefore, one possible quadratic function that could represent h is:
h(x) = (x^2 - 64)
where a is any non-zero constant.