Solution.
Henry's law states that the solubility of a gas in liquids at a constant temperature is proportional to its pressure. We write the formula:
�
=
�
×
�
S=K×P
The Henry's constant for each substance is individual, so we express it and find it through the solubility of the gas and its pressure.
�
=
�
�
K=
P
S
�
=
5.58
∗
1
0
−
6
K=5.58∗10
−6
And now we find the solubility of the gas at a different pressure.
S = 1.39 g/L
Answer:
S = 1.39 g/L
2.
Solution.
To begin with, we will translate the pressure from mm Hg of the column and from atmospheres to Pascals.
760 mmHg = 101324.72 Pa
2.5 atm = 253312.5 Pa
�
=
�
×
�
S=K×P
�
=
�
�
K=
P
S
�
=
1.58
∗
1
0
−
5
K=1.58∗10
−5
Now we find the solubility of the gas at a different pressure.
S = 4.00 g/L
Answer:
S = 4.00 g/L
3.
Solution.
To begin with, we will translate the pressure from atmospheres to Pascals.
0.750 atm = 75993.75 Pa
�
=
�
×
�
S=K×P
�
=
�
�
K=
P
S
�
=
3.22
∗
1
0
−
5
K=3.22∗10
−5
Now we find the gas pressure to get a solution with a concentration of 6.25 g / L.
�
=
�
�
P=
K
S
P = 194.1 kPa
Answer:
P = 194.1 kPa