Question

5.2643mol of ethane is held at 0.9035 atm and 506.25 °C. what is the volume in liters?

Answer 1

To find the volume of ethane , we can use the Ideal gas law. Which states -

`\:\:\:\:\:\:\:\:\:\star\longrightarrow \sf \underline{PV=nRT} \\`

Where:-

• P is the pressure measured in atmospheres
• V is the volume measured in liters
• n is the number of moles.
• R is the ideal gas constant (0.0821 L atm mol⁻¹ K⁻¹).
• T is the temperature measured in kelvin.

As per question, we are given that-

• P=0.9035 atm
• n=5.2643 moles
• T = 506.25°C = 506.25+273 = 779.25 K
• R = 0.0821 L atm mol⁻¹ K⁻¹

Now that we have all the required values, so we can put them all in the Ideal gas law formula and solve for Volume -

`\:\:\:\:\:\:\:\:\:\star\longrightarrow \sf \underline{PV=nRT} \\`

`\:\:\:\:\:\:\:\:\:\longrightarrow \sf 0.9035 * V= 5.2643* 0.0821 * 779.25\\`

`\:\:\:\:\:\:\:\:\:\longrightarrow \sf 0.9035 * V= 336.791\\`

`\:\:\:\:\:\:\:\:\:\longrightarrow \sf V= (336.791)/(0.9035)\\`

`\:\:\:\:\:\:\:\:\:\longrightarrow \sf V= 372.762......\\`

`\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{V= 372.762 \: L}\\`

• Therefore, the volume of ethane is 372.762 L.