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Find the distance between the point (2,1) and the line 3x- 4y+15=0​

User Ente
by
8.3k points

2 Answers

6 votes

Correct answers 5.4

Distance from point (2,3) to the line 3x+4y+9=0

=>r=

3

2

+4

2

∣3(2)+4(3)+9∣

=>r=

9+16

∣16+12+9∣

=>r=

5

27

=>r=5.4

User Bostonou
by
8.5k points
3 votes

Answer:

Explanation:

3

x

4

y

+

15

=

0

.

y

=

3

4

x

1

2

User Vasis
by
8.1k points

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