Question

What are the ordered pair solutions

for this system of equations?
y = -x² + 2
y = x
First, set the equations equal to each other and
move everything to one side.
A:-x²+x+2=0
C:-x² + 2 = x
B:x²+x-2 = 0
D:x²+x+2=0

Answer 1

To find the ordered pair solutions, we need to solve the system of equations by setting them equal to each other:

-x² + x + 2 = x

Simplifying:

-x² + 2x + 2 = 0

We can solve for x using the quadratic formula:

x = (-2 ± sqrt(2^2 - 4(-1)(2))) / (2(-1))

x = (-2 ± sqrt(12)) / (-2)

x = 1 ± sqrt(3)

So the x-values of the ordered pair solutions are:

x = 1 + sqrt(3)

x = 1 - sqrt(3)

To find the corresponding y-values, we can substitute these x-values into either equation. Let's use y = x:

When x = 1 + sqrt(3):

y = 1 + sqrt(3)

When x = 1 - sqrt(3):

y = 1 - sqrt(3)