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how many moles of helium gas are present in a 11.2l container at 298k and 1.35 atm the gas constant r =0.0821 atm/k mol

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Answer

The first step is to use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Rearranging the equation to solve for n, we get:

n = PV/RT

Substituting the given values, we get:

n = (1.35 atm) x (11.2 L) / [(0.0821 atm·L/mol·K) x (298 K)]

n = 0.553 mol

Therefore, there are 0.553 moles of helium gas present in the 11.2L container at 298K and 1.35 atm.

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