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Distance between (1,5) and (-6,-2)

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\:\: \:\: \:\star We are asked to find out the distance between (1,5) and (-6,-2).We know the formula to find the distance between two points is given by -


\:\: \star \underline{ \sf{ Distance = √( (y_2 -y_1)^2 + (x_2-x_1)^2)}}\\

As per question, points are -

  • A (1,5)

  • B(-6,-2)

Now that we are given the points, so we can put them into the formula and solve for distance between them.Which is -


\:\: \:\: \:\star \underline{ \sf{ Distance = √( (y_2 -y_1)^2 + (x_2-x_1)^2)}}\\


\longrightarrow \sf Distance_((AB)) = √( (-2-5)^2 + (-6-1)^2 )\\


\:\:\:\:\:\longrightarrow \sf Distance_((AB))= √( (-7)^2 + (-7)^2 )\\


\:\:\:\:\longrightarrow \sf Distance_((AB)) = √( 49+49 )\\


\: \:\:\:\: \:\longrightarrow \sf Distance _((AB))= √( 98)\\


\: \:\:\: \:\longrightarrow \sf Distance_((AB)) = √(49 * 2)\\


\:\: \:\: \:\:\longrightarrow \sf\underline{ Distance_((AB)) = 7√2}\\


\: \:\:\: \:\:\longrightarrow \sf Distance_((AB) )= 9.89949......\\


\: \:\:\: \:\:\longrightarrow \sf \underline{Distance_((AB) )= 9.9\:(Approx)}\\

Therefore, the distance between (1,5) and (-6,-2) is 7√2 or, 9.9 ( Approx).

User GoldenaArcher
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