Question

each team has a race one racer runs 5/6 the second racer swims 1/12 the third racer bicycles 7/8 what is the total distance the team must cover

Answer 1

Explanation:

First, you need to find the least common denominator (LCD) of 6, 12 and 8. 6 factors to 2*3, 12 to 2*2*3 and 8 to 2*2*2. The LCD will be the number that incorporates the combination that includes all the unique factors, which would be 2*2*2*3 or 24. 5/6 = 20/24, 1/12 = 2/24 and 7/8 = 21/24 so altogether the team covers

(20+2+21)/24 = 43/24 = 1 19/24 miles