Question

For the reaction below, how many moles of Nitrogen are required to produce 18 mol of NH3? N₂ + 3H₂ -> 2 NH3.

Answer 1

9mol N

Step-by-step explanation:

The balanced chemical equation is:

N₂ + 3H₂ → 2NH₃

According to the stoichiometry of this reaction, 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

So, to produce 2 moles of NH₃, we need 1 mole of N₂.

Therefore, to produce 18 moles of NH₃, we would need:

18 mol NH₃ × (1 mol N₂ / 2 mol NH₃) = 9 mol N₂

Thus, 9 moles of nitrogen are required to produce 18 mol of NH₃.