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Solve2x^2-6x+5 by completing the square

User Chantalle
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1 Answer

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2(x-3/2)^2+1/2

Step-by-step explanation:

1. Move the coefficient of x to the front and write the rest normally divided by the coefficient.

2(x^2-3x+5/2)

2. Divide the coefficient of x by 2 squared.

2[x^2-3x+(-3/2)^2-(-3/2)^2+5/2]

3. Put the first terms into ( )^2

2[(x-3/2)^2-9/4+5/2]

4. Add the last 2 terms

2(x-3/2)^2+1/2
User RTigger
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