Question

A cyclist is travelling along a straight path at 5.5 m/s.

The cyclist accelerates uniformly to a speed of 11.0 m/s.
The acceleration of the cyclist is 1.2 m/s².
Calculate the distance travelled by the cyclist during this acceleration.
Give your answer correct to 2 significant figures.
Use the equation: v² - u² = 2 x a x X

Answer 1

37.5 meters

Step-by-step explanation:

We can use the equation:

v² - u² = 2ax

where v is the final velocity, u is the initial velocity, a is the acceleration, and x is the distance travelled during the acceleration.

We are given:

u = 5.5 m/s

v = 11.0 m/s

a = 1.2 m/s²

Substituting these values into the equation, we get:

11.0² - 5.5² = 2 × 1.2 × x

Simplifying the equation, we get:

120.25 - 30.25 = 2.4x

90 = 2.4x

x = 37.5 meters

Therefore, the distance traveled by the cyclist during the acceleration is 37.5 meters (to 2 significant figures).