Question

The ratio of A to B is 1 : 2 and B to C is 3 : 4. If C has the value of 32, what is the sum of the three numbers?

Answer 1

A + B + C = 68

Explanation:

A : B = 1 : 2

B : C = 3 : 4

Find the LCM of 2 and 3. LCM = 6

Multiply A : B by 3 and B : C by 2

`(A)/(B)=(1)/(2)=(1*3)/(2*3)=(3)/(6)\\\\\\(B)/(C )=(3)/(4)=(3*2)/(4*2)=(6)/(8)`

A : B = 3 : 6 & B : C = 6 :8

A : B : C = 3 : 6 : 8

A = 3x

B = 6x

C = 8x

It is given that C is 32.

8x = 32

Divide both sides by 8

x = 32÷ 8

x = 4

A = 3*4 = 12

B = 6 * 4 = 24

Sum of three numbers = 12 + 24 + 32

= 68