Question

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Find the first three terms of the sequence below.
Tn = 2n^2-4n-3

T1=
T2=
T3=

Answer 1

- 5 , - 3 , 3

Explanation:

to find the first three terms, substitute n = 1, 2, 3 into the explicit formula

`T_(n)` = 2n² - 4n - 3

T₁ = 2(1)² - 4(1) - 3

= 2(1) - 4 - 3

= 2 - 7

= - 5

T₂ = 2(2)² - 4(2) - 3

= 2(4) - 8 - 3

= 8 - 11

= - 3

T₃ = 2(3)² - 4(3) - 3

= 2(9) - 12 - 3

= 18 - 15

= 3

the first three terms are - 5, - 3 , 3