Question

I need help please!!!!

Answer 1

we need 19.52 g of sugar to produce 10 g of ethanol.

Step-by-step explanation:

The balanced chemical equation for the fermentation of glucose (sugar) to ethanol (C2H5OH) is:

C6H12O6 → 2C2H5OH + 2CO2

From the equation, we can see that one mole of glucose (C6H12O6) reacts to produce two moles of ethanol (C2H5OH). To determine how many grams of sugar are needed to produce 10g of ethanol, we need to use stoichiometry and the molar mass of glucose.

The molar mass of glucose is 180.16 g/mol, and the molar mass of ethanol is 46.07 g/mol. Therefore, we can calculate the number of moles of ethanol produced from 10 g as follows:

moles of C2H5OH = mass / molar mass = 10 g / 46.07 g/mol = 0.217 moles

Since two moles of ethanol are produced from one mole of glucose, we can calculate the number of moles of glucose needed as follows:

moles of glucose = 0.217 moles / 2 = 0.1085 moles

Finally, we can calculate the mass of glucose needed as follows:

mass of glucose = moles of glucose × molar mass of glucose

mass of glucose = 0.1085 moles × 180.16 g/mol

mass of glucose = 19.52 g

Answer 2

`\:\:\:\:\:\: \sf \underline{\pink{C_6H_(12)O_6} \longrightarrow \pink{2\:C_2H_5OH}+2CO_2}\\`

As per this equation, 1 mole of
`\sf C_6H_(12)O_6` produces 2 moles of
`\sf C_2H_5OH` and 2 moles of
`\sf CO_2`

Molar mass of 1 mole of
`\sf C_6H_12O_6`-

`\:\:\:\:\:\:\longrightarrow \sf Molar\: Mass_{( C_6H_(12)O_6 )} = 12* 6 + 1* 12 + 16 * 6\\`

`\:\:\:\:\:\:\longrightarrow \sf Molar\: Mass_{( C_6H_(12)O_6 )} =\underline{180 \:grams }\\`

Molar Mass of 2 moles of
`\sf C_2H_5OH`-

`\:\:\:\:\:\:\longrightarrow \sf Molar \:Mass _(( C_2H_5OH)) = 2\bigg(12 *2 + 1* 5 + 16 +1\bigg)\\`

`\:\:\:\:\:\:\longrightarrow \sf Molar \:Mass _(( C_2H_5OH)) =2* 46 \\`

`\:\:\:\:\:\:\longrightarrow \sf Molar \:Mass _(( C_2H_5OH)) =\underline{92\: grams }\\`

As per equation, 92 grams of
`\sf C_2H_5OH` can be produced from 180 grams of sugar. So, for making 10 grams of
`\sf C_2H_5OH`,we have to multiply 180 by 10 and then divide by 92. 180 grams of sugar is needed to make 92 grams of ethanol. Therefore -

`\:\:\:\:\:\:\longrightarrow \sf (180* 10)/(92)\\`

`\:\:\:\:\:\:\longrightarrow \sf \underline{\pink{19.565 \:grams }}\\`

19.565 grams of sugar will be needed to make 10 g
`\sf C_2H_5OH`