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Opal makes $12 per hour working for a photographer. She also coaches a competitive soccer team for $7 per hour. Opal needs to earn at least $150 per week, but she does not want to work more than 20 hours per week. A. Create a systems of inequalities to represent this situation. B. Give 2 possible solutions to describe how opal might meet her goals. C. Is (10,6) a solution? Explain.

User AndaluZ
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Answer: A. Let's use x to represent the number of hours Opal works for the photographer, and y to represent the number of hours she coaches soccer. Then we can create the following system of inequalities to represent the situation:

12x + 7y ≥ 150 (Opal needs to earn at least $150 per week)

x + y ≤ 20 (Opal cannot work more than 20 hours per week)

B. There are different ways Opal can meet her goals, but here are two possible solutions:

Solution 1: Opal works for the photographer for 10 hours and coaches soccer for 10 hours. Then her total earnings for the week would be:

12(10) + 7(10) = 120 + 70 = $190

This meets her goal of earning at least $150 per week, and it also satisfies the constraint that she cannot work more than 20 hours per week.

Solution 2: Opal works for the photographer for 15 hours and coaches soccer for 5 hours. Then her total earnings for the week would be:

12(15) + 7(5) = 180 + 35 = $215

This also meets her goal of earning at least $150 per week, and it satisfies the constraint that she cannot work more than 20 hours per week.

C. To check if (10,6) is a solution to the system of inequalities, we need to substitute x = 10 and y = 6 into both inequalities and see if they are true:

12(10) + 7(6) ≥ 150

120 + 42 ≥ 150

162 ≥ 150 (true)

10 + 6 ≤ 20 (true)

Since both inequalities are true, (10,6) is a solution to the system. However, this solution does not meet Opal's goal of earning at least $150 per week, as her total earnings would be:

12(10) + 7(6) = 120 + 42 = $162

So, while (10,6) satisfies the constraints of the system, it is not a valid solution to the problem.

Explanation:

User Lotz
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