Question

4. An ice skater is spinning on the ice at 4.00 rev/s. If the skater’s nose is 0.120 m from the axis of rotation, what is the centripetal acceleration of his nose?

Answer 1

a = 3.02 m/s^2

h

Step-by-step explanation:

we know that centripetal acceleration (a) is

`\frac{v {}^(2) }{r} = a`

since v = rω, we can substitute it into the equation, which now gives us the centripetal acceleration in terms of angular velocity and radius (check image).

now we use the values given and find the answer