Question

what is the final volume of 5.31L of an ideal gas when heated from 200 K to 300 K at constant pressure?

Answer 1

Charles's Law-

`\:\:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow\sf \underline{(V_1)/(T_1)=(V_2)/(T_2)}\\`

Where:-

• V₁ = Initial volume
• T₁ = Initial temperature
• V₂ = Final volume
• T₂ = Final temperature

As per question, we are given that -

• V₁ =5.31L
• T₁ = 200K
• T₂ = 300K

Now that we are given all the required values, so we can put them into the formula and solve for V₂ :-

`\:\:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow\sf \underline{(V_1)/(T_1)=(V_2)/(T_2)}\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2= (V_1)/(T_1)* T_2\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2= (5.31)/(200)* 300\\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 = 0.02655* 300\\`

`\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf V_2=7.965 \\`

`\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf\underline{ V_2 = 7.965\: L}\\`

Therefore, the final volume of 5.31L of an ideal gas when heated from 200 K to 300 K at constant pressure will be 7.965 L.