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What is the area of a right triangle with a height of sixteen and three-fourths meters and a base of 45 meters?

2 Answers

4 votes

The area of a right triangle is given by the formula:

Area = 1/2 * base * height

Substituting the values given in the problem:

Area = 1/2 * 45 meters * 16 and 3/4 meters

To simplify the computation, we convert the mixed fraction 16 and 3/4 to an improper fraction:

16 and 3/4 = (16 * 4 + 3) / 4 = 67/4 meters

Substituting this value, we get:

Area = 1/2 * 45 meters * 67/4 meters

Simplifying:

Area = 843.75 square meters

Therefore, the area of the right triangle is 843.75 square meters.

User Salihgueler
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8.0k points
4 votes

Answer: 376 7/8

Step-by-step explanation: if you multiply the base and the height you'll get 754 3/4 since this is a triangle we are talking about it would be halved which would make it 376 7/8.

and im doing the exam and its correct.

User Michael Bobick
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8.8k points