180k views
4 votes
What is the area of a right triangle with a height of sixteen and three-fourths meters and a base of 45 meters?

2 Answers

4 votes

The area of a right triangle is given by the formula:

Area = 1/2 * base * height

Substituting the values given in the problem:

Area = 1/2 * 45 meters * 16 and 3/4 meters

To simplify the computation, we convert the mixed fraction 16 and 3/4 to an improper fraction:

16 and 3/4 = (16 * 4 + 3) / 4 = 67/4 meters

Substituting this value, we get:

Area = 1/2 * 45 meters * 67/4 meters

Simplifying:

Area = 843.75 square meters

Therefore, the area of the right triangle is 843.75 square meters.

User Salihgueler
by
8.2k points
4 votes

Answer: 376 7/8

Step-by-step explanation: if you multiply the base and the height you'll get 754 3/4 since this is a triangle we are talking about it would be halved which would make it 376 7/8.

and im doing the exam and its correct.

User Michael Bobick
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories