Question

2. If Jon took a test and made the following scores: 72, 84, 92, 80, 96, 88, 45, 70, 79, 92, 87, and 103.

a. Box and Whisker plot:
b. What is the range:
IQR:
c. Are there any outliers?
3. If the mean is 77 and the standard deviation is 11 please find:
a.
A value 3 standard deviations above the mean
b.
A value 2.5 standard deviation below the mean
c. A value 2 standard deviations below the mean
d. A value 1 standard deviation above the mean
4. If 99.7 percent of the data is between 30 and 90, then please find the mean and the standard of deviation.
b. o:
a. u
5. If 68 percent of the data is between 42 and 58, then please find the mean and the standard of deviation.
b. a:
a. p
6. If 95 percent of the data is between 34 and 64, then please find the mean and the standard of deviation.
b. a:
a. µ

Someone please help with this page

Answer 1

a)

103

|

96 +

|

92 | *

| * *

88 +--*

| *

84 |

|*

80 +

|

79 |

|

72 +

|

70 |

|

b)b. The range is the difference between the highest and lowest scores: 103 - 45 = 58.

The IQR is the interquartile range, which is the range of the middle 50% of the scores. To find it, we first need to find the first and third quartiles:

The first quartile (Q1) is the median of the lower half of the scores, which are 45, 70, 72, 79, and 80. The median of this set is (72+79)/2 = 75.5.

The third quartile (Q3) is the median of the upper half of the scores, which are 84, 87, 88, 92, and 96. The median of this set is (88+92)/2 = 90.

Therefore, the IQR is 90 - 75.5 = 14.5.

c)c. To find any outliers, we need to first define the "fences" of the box and whisker plot. The lower fence is Q1 - 1.5IQR = 75.5 - 1.514.5 = 53.25. The upper fence is Q3 + 1.5IQR = 90 + 1.514.5 = 112.75.

There is one score that is outside the fences: 103. Therefore, 103 is an outlier.

Explanation: