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Two +1 C charges are separated by 300m. What is the magnitude of the electric force between them

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Answer:

1000 N

Step-by-step explanation:

The electric force between two charges is given as

F = kq'q/r²......................... Equation 1

Where F = electric force between the charges, q' = magnitude of the first charge, q = magnitude of the second charge, r = distance between the charges, k = coulombs constant

Given: q' = q = 1 C, r = 3000 m, k = 9×10⁹ Nm²/kg²

Substitute into equation 2

F = 1²×(9×10⁹)/3000²

F = 1000 N.

Hence the magnitude of the electric force between them = 1000 N

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