Question

URGENT!!!

A small glass ball is rubbed with a piece of silk, giving the ball a charge of 1.0 x 10^-8 C. determine the magnitude of the force due to the Earth's magnetic field if the ball is thrown to the west with a velocity 8.0 m/s .
The earth's magnetic field is 5.0 x 10^-5 T

Answer 1

• 
  `F = 3* 10^(-12) \ N`

Step-by-step explanation:

To find:-

• The magnitude of force due to Earth's magnetic field.

Answer:-

We are here given that, a ball having a charge of 1*10-⁸C is thrown with a velocity of 8m/s towards west . We are interested in finding out the magnetic force due to the earth .

As we know that, the magnetic force is given by,

`\longrightarrow\boxed{ F = q[\vec{v} * \vec{B} ]} \\`

So here we have,

• q = 1 * 10-⁸ C
• v = 6m/s West
• B = 5*10-⁵ T

So on substituting the respective values, we have;

`\longrightarrow F = 10^(-8) C [ v B \sin\theta ] \\`

Here
`\theta` is the angle between velocity and the magnetic field, which is here 90° . So that, we have;

`\longrightarrow F = 10^(-8) C [ 6 \ m/s * (5* 10^(-5) \ T) * \sin90^o \\`

The value of sin90° is " 1 " . So we have;

`\longrightarrow F = 10^(-8) * 30 * 10^(-5) * 1 \ N \\`

`\longrightarrow F = 30 * 10^(-13) \ N \\`

`\longrightarrow \boxed{\boldsymbol{ F = 3 * 10^(-12) N }}\\`

This is the required magnetic force by the earth's magnetic field.