Question

The Area of a Rectangle is 40. The width is 2 less than 3

times the length. Find the width.
O 10
O 12
O 15
O 14

Answer 1

Let Length= x, Width= y

A.t.c.

3x-2=y ...(1)

Area = length × width

= xy = 40

from (1)

`x(3x - 2) = 40 \\ 3 {x}^(2) - 2x = 40 \\ 3 {x}^(2) - 2x - 40 = 0 \\ 3 {x}^(2) - 12x + 10x - 40 = 0 \\ 3x(x - 4) + 10(x - 4) = 0 \\ (3x + 10)(x - 4) = 0 \\ x = - (10)/(3) \: or \: 4`

neglecting -10/3

length = 4

width = 3(4)-2=12-2

= 10