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5 votes
The perimeter of a rectangle is 60, and the width is 3 times

the length. What is the width?
O24.5
O 26.5
O 22.5
O 20.5

User JohnnyF
by
7.9k points

2 Answers

2 votes

Answer:

Answer: 22.5

Explanation:

Let L be the length of the rectangle, and W be the width.

From the problem, we know that:

The perimeter of the rectangle is 60, which means that:

2(L + W) = 60

L + W = 30

The width is 3 times the length:

W = 3L

Substituting W = 3L into the first equation, we get:

L + 3L = 30

4L = 30

L = 7.5

Therefore, the width is:

W = 3L = 3(7.5) = 22.5

So, the width of the rectangle is 22.5. Answer: 22.5

User Orschaef
by
7.6k points
3 votes

Let's assume that the length of the rectangle is "x".

Since the width is 3 times the length, the width can be represented as "3x".

The perimeter of a rectangle is given by the formula:

P = 2(l + w)

where P is the perimeter, l is the length, and w is the width.

Substituting the values given in the problem, we have:

60 = 2(x + 3x)

Simplifying, we get:

60 = 8x

Dividing both sides by 8, we get:

x = 7.5

Now that we know the length, we can find the width:

width = 3x = 3(7.5) = 22.5

Therefore, the width of the rectangle is 22.5.

User MaikoID
by
9.1k points

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