Question

A bag contains 8 red marbles, 3 blue marbles, and 4 green marbles. What is the probability

. Carlos draws a green marble, does not replace it, and then draws another green marble?
4/15
16/225
54/210
2/35

Answer 1

To solve this problem, we use the rule of conditional probability which states that the probability of the joint event A and B happening is equal to the probability of A happening multiplied by the probability of B happening given that A has already happened.

So, the probability of drawing a green marble on the first draw is 4/15, since there are 4 green marbles out of a total of 15 marbles.

If the first marble drawn is green and not replaced, there are now 14 marbles remaining in the bag, out of which 3 are green.

Thus, the probability of drawing another green marble given that the first one was green is 3/14.

Therefore, the probability of drawing two green marbles without replacement is:

(4/15) * (3/14) = 2/35

So the answer is 2/35.