Question

Determine the mass of CO2 gas that has a volume of 7.10 L at a pressure of 1.11 atm and a temperature of 31.0°C.

Answer 1

Answer: 14.11 g

Step-by-step explanation:

Ideal gas law

We will use the ideal gas law for this problem:

`PV=nRT`

We know V, which is 7.10

P is 1.11 atm

and T is 31.0 C, or 305 K

R will be 0.08206 L*atm/mol*k, since we are dealing with atmospheres for our pressure.

Now, we just need to solve for n, moles

`1.11*7.10=n*0.08206*305\\n=0.321`

We have 0.321 moles of CO2

Convert to g

The molar mass of CO2 is 44.01 g/mol, so we multiply 44.01 g/mol by 0.321 moles to cancel out the moles and get grams.

`(44.01g)/(mol) *0.321mol=14.11 g`