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(-3+i)^2 in simplest a + bi form

User ProxyTech
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1 Answer

5 votes

Answer:


\boxed{8-6i}

Explanation:

First, we developed the square binomial
(-3+\mathrm{i})^2.


\implies (-3+\mathrm{i})(-3+\mathrm{i})\\9-3\mathrm{i}-3\mathrm{i}+i^2\\9-6\mathrm{i}+\mathrm{i}^2

Remember the next product:


i^2= \mathrm{i} * \mathrm{i} = -1

then:


9-6\mathrm{i}+ (-1)\\8-6i

Hope it helps


\text{-B$\mathfrak{randon}$VN}

User Nik Shenoy
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