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A car acquires velocity of 72km/h

in 10s starting from start.. Calculate it's average velocity, acceleration and distance travelled during this period. ​

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Answer:

Avg. Velocity = 10 m/s

Acceleration = 2 m/s^2

Distance = 100 m

Step-by-step explanation:

First, we need to convert the velocity of the car from km/h to m/s, since the standard unit of velocity in SI units is meters per second.

72 km/h = 20 m/s (to 2 significant figures)

We can now calculate the average velocity of the car using the formula:

average velocity = total distance ÷ total time

Since the car starts from rest, its initial velocity is 0 m/s. Therefore, the total distance it travels during the 10 seconds is:

distance = (1/2) × acceleration × time²

where acceleration is the constant acceleration of the car during the 10 seconds, which we do not know yet.

To find the acceleration, we can use the formula:

final velocity = initial velocity + acceleration × time

The final velocity of the car is 20 m/s (which we calculated earlier), the initial velocity is 0 m/s, and the time is 10 seconds. Therefore:

20 m/s = 0 m/s + acceleration × 10 s

Solving for acceleration:

acceleration = 2 m/s²

Substituting this value of acceleration into the formula for distance, we get:

distance = (1/2) × 2 m/s² × (10 s)² = 100 meters

Therefore, the average velocity of the car during the 10 seconds is:

average velocity = total distance ÷ total time = 100 meters ÷ 10 seconds = 10 m/s

The acceleration of the car during the 10 seconds is 2 m/s², and the distance travelled by the car during this period is 100 meters.

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