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The product of two numbers divided by four is equal to ten sum of nine and ten

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Let the first number be x and the second number be y. Then we have:

xy/4 = 10 + 9 + 10

Simplifying the right side:

xy/4 = 29

Multiplying both sides by 4:

xy = 116

Now we need to find two numbers whose product is 116. We can start by listing the factors of 116:

1, 2, 4, 29, 58, 116

Since we are looking for two numbers whose product is 116, we can try pairs of factors until we find a pair that works:

1 x 116 = 116 (not a sum of two numbers)

2 x 58 = 116 (sum is 60, not 19)

4 x 29 = 116 (sum is 33, not 19)

So the only pair that works is:

x = 29 and y = 4

Let's check if these values satisfy the original equation:

xy/4 = 29 x 4 / 4 = 29 = 10 + 9 + 10

So the solution is x = 29 and y = 4.

User Mattrick
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