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A car slows down at -5.00m/s^2 until it comes to a stop traveling 15.0m. How much time did it take to stop? (Unit=s)

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A car slows down at -5.00m/s^2 until it comes to a stop traveling 15.0m. How much-example-1

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Answer: 2.45 s

Explanation;

To solve this problem, we can use one of the equations of motion:

final velocity² = initial velocity² + 2 × acceleration × distance

Since the car comes to a stop, the final velocity will be 0 m/s. We are given the acceleration (-5.00 m/s²) and the distance (15.0 m). We need to find the initial velocity first, and then we can find the time it took to stop.

0 = initial velocity² + 2 × (-5.00 m/s²) × 15.0 m

Solving for the initial velocity:

initial velocity² = 2 × 5.00 m/s² × 15.0 m = 150.0 m²/s²
initial velocity = √150.0 m²/s² ≈ 12.25 m/s

Now we can use another equation of motion to find the time it took to stop:

final velocity = initial velocity + acceleration × time

0 = 12.25 m/s + (-5.00 m/s²) × time

Solving for the time:

time = (12.25 m/s) / (5.00 m/s²) ≈ 2.45 s

So, it took approximately 2.45 seconds for the car to come to a stop.
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