Question

Acetylene (C₂H₂) gas is often used in welding torches because of the very high heat produced when it reacts with oxygen (O₂) gas, producing carbon dioxide

gas and water vapor. Calculate the moles of water produced by the reaction of 2.2 mol of acetylene. Be sure your answer has a unit symbol, if necessary, and
round it to the correct number of significant figures

Answer 1

Answer: 2.2 moles

Step-by-step explanation:

To calculate the moles of water produced, we first need to write down the balanced chemical equation for the combustion of acetylene:

C₂H₂(g) + O₂(g) → CO₂(g) + H₂O(g)

To balance the equation, we need to make sure that there are the same number of atoms for each element on both sides of the equation. The balanced equation is:

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

Now we can use stoichiometry to find the moles of water produced:

2.2 mol C₂H₂ * (2 mol H₂O / 2 mol C₂H₂) = 2.2 mol H₂O

So, 2.2 moles of acetylene will produce 2.2 moles of water when reacted with a sufficient amount of oxygen.