Question

O₂(g) + 2 H₂(g) →2 H₂O

The rate law for this reaction is second order in H₂ and first order in O₂. Write the rate
law.
If the rate constant for this reaction at 1000 K is 6.0 x 104 M²s¹, what is the reaction
rate when [0₂] = 0.055 M and [H₂] = 0.015 M?

Answer 1

9.94 x 10^-6 M/s

Step-by-step explanation:

The rate law for the given reaction is:

Rate = k[O₂][H₂]²

where k is the rate constant, [O₂] is the concentration of O₂, and [H₂] is the concentration of H₂.

Using the given values, we can substitute them into the rate law and solve for the reaction rate:

Rate = (6.0 x 10^4 M²s^-1) x (0.055 M) x (0.015 M)²

Rate = 9.94 x 10^-6 M/s

Therefore, the reaction rate when [O₂] = 0.055 M and [H₂] = 0.015 M is 9.94 x 10^-6 M/s.