Final answer:
In the reaction of isopropylbenzene with NBS under UV light, a radical bromination occurs, producing bromoisopropylbenzene as the sole product due to the formation of the most stable secondary free radical intermediate.
Step-by-step explanation:
Mechanism for the Reaction of Isopropylbenzene with NBS
When isopropylbenzene (cumene) is treated with NBS (N-Bromosuccinimide) and irradiated with UV light, a radical bromination reaction occurs. The reaction is selective due to the formation of the most stable free radical intermediate. Here is a step-by-step explanation:
UV light initiates the reaction by homolytically cleaving the N-Br bond in NBS, forming a bromine radical.
The bromine radical abstracts a hydrogen atom from the isopropyl group of cumene, leading to the formation of the most stable (secondary) free radical adjacent to the phenyl group. This is because secondary radicals are more stable than primary radicals.
The cumene radical reacts with a new bromine molecule to form the final product, which is bromoisopropylbenzene.
The bromine atom from this reaction can then go on to react with another NBS molecule, perpetuating the chain reaction.
Only one product is formed because the radical intermediate forms at the position which leads to the greatest stability, which in this case is the secondary carbon of the isopropyl group. This carbon is more substituted and adjacent to the aromatic ring, which provides additional stability through resonance.