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What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.490N and the coefficient of friction is 0.250?
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Aug 1, 2024
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What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.490N and the coefficient of friction is 0.250?
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Shachilies
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Answer:
F=0.1225N
Step-by-step explanation:
μ=F/R
0.250=F/0.490
F=0.1225N
Patto
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Aug 7, 2024
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