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The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury (II) oxide.

HgO(s) --> Hg(l) + 1/2O2(g) ΔH° = 90.84 kJ
Use the data given below to determine DS = and the temperature, at which this reaction will become spontaneous under standard conditions.
S°(Hg) = 76.02 J/K· mol
S°(O2) = 205.0 J/K· mol
S°(HgO) = 70.29 J/K· mol

1 Answer

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Answer:

S°(Hg) = 76.02 J/K· mol

Step-by-step explanation:

User Mohammad Dohadwala
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