How much heat is needed to warm 250 g of water from 22 °C to 98 °C? The specific heat of water is 4.18 J/g K?

asked Oct 12, 2024 127k views

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5 votes

Answer: 79420J or 79.420 Kj

Step-by-step explanation:

q=mc(t2-t1)

250g x 4.18J/g K x (98C-22C)= 79420J

Knogobert answered Oct 17, 2024

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