Given the following equation (x+12)² + (y+3)² = 9, what is the diameter? Your Answer 3 6 9 12 Help!!! I know the answer but can you explain how to get the diameter???

Question

asked Oct 15, 2024 149k views

1 Answer

Neoswf · Answer 1 · 2024-10-18T19:35:46+0000

Write properties of circle:

classify: circle

equation in general form:
x^2+y^2+6y+24x+144=0

equation in standard form:
(x+12)^2 + (y+3)^2 = 9

center:
(-12,-3)

radius:

diameter:
$\bold{6}$

area:
$9\pi$

circumference:
$6\pi$

domain:
$-15\leq x\leq -9$

range:
$-6\leq y\leq 0$

Therefore, the diameter of the equation
$\bold{(x+12)^2 + (y+3)^2 = 9}$ is 6