Question

Given the following equation (x+12)² + (y+3)² = 9, what is the diameter?

Your Answer
3
6
9
12
Help!!! I know the answer but can you explain how to get the diameter???

Answer 1

Write properties of circle:

classify: circle

equation in general form:
`x^2+y^2+6y+24x+144=0`

equation in standard form:
`(x+12)^2 + (y+3)^2 = 9`

center:
`(-12,-3)`

radius:
`3`

diameter:
`\bold{6}`

area:
`9\pi`

circumference:
`6\pi`

domain:
`-15\leq x\leq -9`

range:
`-6\leq y\leq 0`

Therefore, the diameter of the equation
`\bold{(x+12)^2 + (y+3)^2 = 9}` is 6