Question

Find the length of side AB.

Give your answer to 1 decimal place.
CB = 12 cm
AB = 62°

PLEASE HELP!! ​

Answer 1

AB ≈ 5.6 cm

Explanation:

Using the cosine ratio in the right triangle

cos62° =
`(adjacent)/(hypotenuse)` =
`(AB)/(BC)` =
`(AB)/(12)` ( multiply both sides by 12 )

12 × cos62° = AB , then

AB ≈ 5.6 cm ( to 1 dec. place )