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1 Answer

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1. We can use the difference of squares identity to factorize this expression:

(5y-6)²-81 = [(5y-6) + 9][(5y-6) - 9]

Now we simplify each factor:

[(5y-6) + 9] = 5y + 3

[(5y-6) - 9] = 5y - 15

Therefore,

(5y-6)²-81 = (5y + 3)(5y - 15)

2. We can use the square of a binomial formula to expand the expression:

1 - (2x-1)² = 1 - (2x)² + 2(2x)(-1) + (-1)²

= 1 - 4x² - 4x + 1

= -4x² - 4x + 2

Now, we can factor out a common factor of -2 from each term:

-2(2x² + 2x - 1)

Therefore,

1 - (2x-1)² = -2(2x² + 2x - 1)

3. Let's begin by simplifying both sides of the equation by combining like terms:

(4.5y+9)-(6.2-3.1y)=7.2y+2.8

4.5y + 9 - 6.2 + 3.1y = 7.2y + 2.8

7.6y + 2.8 = 7.2y + 2.8

Now we can isolate the variable on one side of the equation by subtracting 7.2y from both sides:

7.6y - 7.2y = 2.8 - 2.8

0.4y = 0

Finally, we can solve for y by dividing both sides by 0.4:

y = 0

Therefore, the solution to the equation is y = 0.

4. We can use the difference of squares identity to factorize this expression:

(5c-3d)² - 9d² = [(5c-3d) + 3d][(5c-3d) - 3d]

Now we simplify each factor:

[(5c-3d) + 3d] = 5c

[(5c-3d) - 3d] = 5c - 6d

Therefore,

(5c-3d)² - 9d² = (5c)(5c - 6d)

So, we can write the expression as the product of (5c) and (5c - 6d).

User Vikash Madhow
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