Answer:
d) The speak method defined in the Dog class will be called.
Step-by-step explanation:
In this code, a new instance of the Dog class is created and assigned to a variable of type Animal. When the method speak() is called on this instance using the variable spot, the overridden version of speak() in the Dog class will be called, since method calls are determined at runtime based on the actual object type, not the variable type. Therefore, option d) is the correct answer.